إجابة:
# ص = sintheta / (2sin ^ 2theta + 3cos ^ 2theta-الخطيئة (2theta)) #
تفسير:
لهذا سنحتاج:
# س = rcostheta #
# ذ = rsintheta #
# rsintheta = 2 (rsintheta) ^ 2 + 3 (rcostheta) ^ 2-2 (rcostheta) (rsintheta) #
# rsintheta = 2R ^ ^ 2sin 2theta + 3R ^ ^ 2cos 2theta-2R ^ 2costhetasintheta #
# sintheta = 2rsin ^ 2theta + 3rcos ^-2theta 2rcosthetasintheta #
# sintheta = 2rsin ^ 2theta + 3rcos ^ 2theta-rsin (2theta) #
# sintheta = ص (2sin ^ 2theta + 3cos ^ 2theta-الخطيئة (2theta)) #
# ص = sintheta / (2sin ^ 2theta + 3cos ^ 2theta-الخطيئة (2theta)) #
